[PATCH v7 3/6] seccomp: add a way to get a listener fd from ptrace

Jann Horn jannh at google.com
Thu Oct 11 13:39:37 UTC 2018


On Thu, Oct 11, 2018 at 9:24 AM Paul Moore <paul at paul-moore.com> wrote:
> On October 10, 2018 11:34:11 AM Jann Horn <jannh at google.com> wrote:
> > On Wed, Oct 10, 2018 at 5:32 PM Paul Moore <paul at paul-moore.com> wrote:
> >> On Tue, Oct 9, 2018 at 9:36 AM Jann Horn <jannh at google.com> wrote:
> >>> +cc selinux people explicitly, since they probably have opinions on this
> >>
> >> I just spent about twenty minutes working my way through this thread,
> >> and digging through the containers archive trying to get a good
> >> understanding of what you guys are trying to do, and I'm not quite
> >> sure I understand it all.  However, from what I have seen, this
> >> approach looks very ptrace-y to me (I imagine to others as well based
> >> on the comments) and because of this I think ensuring the usual ptrace
> >> access controls are evaluated, including the ptrace LSM hooks, is the
> >> right thing to do.
> >
> > Basically the problem is that this new ptrace() API does something
> > that doesn't just influence the target task, but also every other task
> > that has the same seccomp filter. So the classic ptrace check doesn't
> > work here.
>
> Due to some rather unfortunate events today I'm suddenly without easy access to the kernel code, but would it be possible to run the LSM ptrace access control checks against all of the affected tasks?  If it is possible, how painful would it be?

There are currently no backlinks from seccomp filters to the tasks
that use them; the only thing you have is a refcount. If the refcount
is 1, and the target task uses the filter directly (it is the last
installed one), you'd be able to infer that the ptrace target is the
only task with a reference to the filter, and you could just do the
direct check; but if the refcount is >1, you might end up having to
take some spinlock and then iterate over all tasks' filters with that
spinlock held, or something like that.



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